Dear All,

If someone can help me please answer for the following problem:

Referring to mandatory appendix 24, chapter 24-4, paragraph (b)(4) please clarify as follow:
we have a quick opening closure with the following data:
Ǿ=5°
µ=5°
in formula (1)Wm1, (2)Wm2, (3)Wm3 please clarify the value to be used for (Ǿ-µ) and (Ǿ+µ).

In order to avoid confusion I prefer to quote my value only during discusion.

Andrea

Andrea,
Can you clarify what is the problem? I used it couple of times and I didn't have problems. Can't you calculate a tangens of some angle?

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Konrad Anikiel

I'm able to calculate a tangent, but please refer to paragraph (b)(4).
Our program (APV) , with input of Ǿ=5 and µ=5 adopt:

Ǿ=10
µ=5
therefore (Ǿ-µ)=5 and (Ǿ+µ)=15.

This is the correct way?

Andrea,
I understand 24-4(b)(4) as the equations shall be read:
Wm1=0.637(H+Hp) tan(max(φ-µ,5deg))
Wm2=0.637 Hm tan(φ+max(µ,5deg))
Wm3=0.637(H+Hp) tan(φ+max(µ,5deg))
Apparently, your software understands it the wrong way, and it doesn't clarify the trick it does behind the screen. This is why I use Mathcad: you can't lie to it and it can't lie to you.

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Konrad Anikiel

Thanks for your prompt answer,

what do you think about paragraph 24-1 (d)?

Reading it literally, it does not apply to your case, because you have 5deg, not 0deg. "total included clamping angle" is not defined, but I understand it's 2*φ, so even if it was 0deg, you would have to use your 5deg. Excellent example of a dumb rule, because what if one has 1deg? It still would not apply! Maybe there is some interpretation. On the other hand, I don't think that there would be a lot of difference in stresses between using φ=0deg or 5deg.

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Konrad Anikiel