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 Post subject: Nozzle weld
PostPosted: Thu Jun 08, 2006 12:57 pm 
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Hi all,

one simple question: Nozzle in Cylinder
Which is the minimal distance between a nozzle weld and the circumferential weld seam of a cylinder?

I reduce the reinforcement length in the UG-37 calc. if their is a circumferential weld in this area but what is the limit?
AD 2000 has a minimal distance for the weld of the bracker reinforcement plate to the circumferential weld seam of the cylinder: lmin = Sqrt(Da * s)
[Da and s are based on the cyl.]

Many thanks

Frank


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 Post subject:
PostPosted: Thu Jun 08, 2006 2:05 pm 
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Hi Frank,

there is no minimum distance between a nozzle and a welded joint, it can even be located in the joint. UG-36(d) refers to "UW-14 Openings in or adjacent to welds". Here you will find the following in bullet point (a):
Code:
Any type of opening that meets the requirements for reinforcement given in UG-37 or UG-39 may be located in a welded joint.


In (b) you will find the RT requirements. In UW-14(d) is the answer regarding the minimum distance if the RT requirements of (b) are not satisfied.

Code:
UW-14(d) Except when the adjacent butt weld satisfies the requirement for radiography in (b) above, the edge of openings in solid plate meeting the requirements of UG-36(c)(3) shall not be placed closer than 1/2 in. (13 mm) from the edge of a Category A, B, or C weld for material 1 1/2 in. (38 mm) thick or less.


That´s it.
Michael


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 Post subject:
PostPosted: Thu Jun 08, 2006 2:54 pm 
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Many thanks for the fast reply.

Frank


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 Post subject:
PostPosted: Fri Jun 09, 2006 12:43 pm 
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Frank,
When a nozzle passes through a circumferential weld, the efficiency of the weld is taken to calculation of reinforcement areas (which is not so clear, when reading UG-37 first sentences under definitions). But the nozzle can pas through a shell-to-head junction. UG-45 should be based on the thicker member then.

Konrad


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 Post subject: reinforcement area A1
PostPosted: Fri Jun 09, 2006 1:56 pm 
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Konrad,
the weld efficiency is only taken into account when the nozzle is located in any other welded joint but a category B butt joint. Welds connecting two cylinders or cylinder-formed head with straight flange are cat. B joints and this means always E1 = 1 for the determination of reinforcement area A1 (independent from the efficiency of the weld).

When attaching a hemi head you´re right, this means a cat. A joint.

Quote:
(which is not so clear, when reading UG-37 first sentences under definitions)

I do not know which sentence you refer.

Best regards
Michael


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 Post subject:
PostPosted: Fri Jun 09, 2006 2:47 pm 
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Right, B is shell course-to another one, or to elliptical head. My mistake, sorry.

I meant "For a circular opening in a cylindrical shell, the plane containing the axis of the shell is the plane of greatest loading due to pressure". Do you remember a topic about split reinforcing pad here not long ago? If the split would be cat. A- then the weld factor should be taken into account, but if it would be B- then it doesn't affect UG-37 requirements. But A and B pertain to shell, not reinf. pads. Maybe UW-3 sould be ammended with reinforcing pads.
Konrad


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 Post subject:
PostPosted: Fri Jun 09, 2006 3:19 pm 
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In my opinion this sentence is associated with Fig. UG-37 and the correction factor F, not with welding. When considering a plane not longitudinal to the vessel (along its axis), the required reinforcement area A can be reduced due to the lower loads (when using Fig. UG-37).

The greatest loadings due to pressure are in the plane containing the axis of the shell, because the circumferential stress is twice the longitudinal, therefore F=1 :arrow: full A.

Michael


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 Post subject:
PostPosted: Fri Jun 09, 2006 3:39 pm 
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Michael, could you please explain me closer what benefit could be taken from fig UG-37? I understand that it depicts that stresses are smaller in different planes, but what is the use of it?

Konrad


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 Post subject:
PostPosted: Fri Jun 09, 2006 4:07 pm 
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When considering a plane not longitudinal to the vessel, you do not need the full required area A for reinforcement. E.g. for the plane in "circumferential" direction, F=0.5. This means considering this plane, A required is A/2. However, normally there is no benefit because you have to calculate the longitudinal plane along the vessel axis in any case.

With factor F you can consider that the circumferential stress is twice the longitudinal:
longitudinal stress = (p D) / (4 t)
circumferential stress = (p D) / (2 t)
(In German it´s called "Bockwurst-Formel" (sausage formula, no joke), because a sausage will always burst along its longitudinal axis.)

I think you can use it if there is an adjacent nozzle near to your nozzle which is not in the same longitudinal plane. Please note that you have to meet the requirements of UW-16(c)(1) (integral reinforcement)
Michael


Last edited by Frohnert on Mon Oct 02, 2006 8:58 am, edited 1 time in total.

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 Post subject:
PostPosted: Fri Jun 09, 2006 8:40 pm 
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Michael,
Thanks. This would mean that an opening reinforcement may be cosidered in many various planes. And this would lead to, for instance, variable width of reinforcing patch required along nozzle's circumference. And, if required width of the reinforcing pad would get 0 in a plane perpendicular to the axis, then we might need, say "8" shaped pad. It might be beneficial in rerating a vessel, when higher MAWP might be acceptable after reinforcing the nozzle-to-shell junctions. If a nozzle is flanged, a split reinforcing pad would not cause to cut the flange off in order to place the pad.

Konrad


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